I'm trying to work with photos in python.
v = droid.pick('content://media/external/images/media')
location = v['result']['data']
I want to ftp this file somewhere, and ftplib works fine (thanks!)
To STOR the file I need to first open() it. I pass the content uri into
open(location) and get no love.
if you can't make open(location) work, could we get a method to resolve a file
uri from a content uri?
see snippet:
http://www.androidsnippets.org/snippets/130/
Original issue reported on code.google.com by snarkh...@gmail.com on 10 Jun 2010 at 10:53
Copied from original issue: damonkohler/android-scripting#346
From @GoogleCodeExporter on May 31, 2015 11:26
Original issue reported on code.google.com by
snarkh...@gmail.com
on 10 Jun 2010 at 10:53Copied from original issue: damonkohler/android-scripting#346