POST All queued files as one job

[SamuelDev]

I am trying to have my implementation of the plugin send all queued files to my controller action at one time. Is there an option to do this natively with this plugin?

I tried setting the queue to false, but this sends all the files in parallel, rather than as one post action.

[bubach]

Needed the exact same thing. As it doesn't seem to support this feature I ended up hacking the source a bit:

In DmUploader.prototype.startAll

            // or upload them all
            for (var i = 0; i < this.queue.length; i++) {
                this.queue[i].upload(this.queue);
                break;
            }

and in start of DmUploaderFile.prototype.upload

    DmUploaderFile.prototype.upload = function(files)
    {
        var files = files || [this];
        var file = this;

        /*
        if (!file.canUpload()) {
            if (file.widget.queueRunning && file.status !== FileStatus.UPLOADING) {
                file.widget.processQueue();
            }
            return false;
        }*/

        // Form Data
        var fd = new FormData();

        for (var e = 0; e < files.length; e++) {
            if (files[e].canUpload()) {
                fd.append(files[e].widget.settings.fieldName, files[e].data);
            }
        }
...

using a array type fieldName as fieldName: 'attachment_files[]', and this for the rest of my form:

                extraData: function() {
                    var paramObj = {};
                    $.each($('#drop-area').closest('form').serializeArray(), function(_, kv) {
                        paramObj[kv.name] = kv.value;
                    });
                    return paramObj;
                }

now it almost works as a normal form, just need to intercept the submit event and call dmUploader('start')

[SamuelDev]

Unfortunately I don't work for the company that I needed to do this for anymore, so I can't post exactly what I did.

Essentially how I solved it was to generate a job id guid with the control, send that back with each file, and send back the queue position of each file. I would store each file locally on the server in a folder with the job guid and once file with position 0 was done uploading, do what I needed to with all the files. Once that was done I would delete the folder with the matching guid.