Open dannywillems opened 7 years ago
Because we compare x_int.t and y_int.t.
In general, recursive types. We can detect we already ask the question.
sig(z) type t = z.t end <: Int.t
Naive: yes. Expected: no.
Because we compare x_int.t and y_int.t.
In general, recursive types. We can detect we already ask the question.