darrylb123
commented
1 year ago Yep, looks like a bug. In the mean time, why not change the one with the trailing underscore to remove it. You can use the device path to change the name. Find out the device path for your relay, it seems to be the same as the documentation (/dev/hidraw4) . Use usbrelay -v to find the device path From the documentation: $ sudo usbrelay ZXCV_1=0 ZXCV_2=0
$ sudo usbrelay ZXCV_0=ZAQ12 # or /dev/hidraw4_0=ZAQ12 ZXCV_1=0 ZXCV_2=0 Setting new serial
$ sudo usbrelay ZAQ12_1=0 ZAQ12_2=0
Darryl
On Tue, Jan 17, 2023 at 7:42 AM wasikan-git @.***> wrote:
Hi, I think there's a bug in the code. I've a relay which identifies itself (sudo usbrelay -e /dev/hidraw4) as:
ELSD__1=0 IDSERIAL=ELSD
Please note underscore as a last character of ID_SERIAL.
sudo usbrelay -d gives:
libusbrelay: 1.0-2bpo11+1 usbrelay: 1.0-2bpo11+1 enumerate_relay_boards()Found 1 devices Device Found type: 16c0 05df path: /dev/hidraw4 serialnumber: ELSD Manufacturer: www.dcttech.com Product: USBRelay1 Release: 100 Interface: 0 Number of Relays = 1 Module_type = 1 ELSD__1=0
and sudo usbrelay ELSD1=1 Invalid relay specification: ELSD1=1
I also have another relay of the same type but its ID_SERIAL does not end with underscore. This relay works as expected. Hopefully usbrelay can be fixed without too much trouble.
Regards Andrzej
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wasikan-git
Hi, I think there's a bug in the code. I've a relay which identifies itself (sudo usbrelay -e /dev/hidraw4) as:
ELSD__1=0 IDSERIAL=ELSD
Please note underscore as a last character of ID_SERIAL.
sudo usbrelay -d gives:
libusbrelay: 1.0-2~bpo11+1 usbrelay: 1.0-2~bpo11+1 enumerate_relay_boards()Found 1 devices Device Found type: 16c0 05df path: /dev/hidraw4 serialnumber: ELSD Manufacturer: www.dcttech.com Product: USBRelay1 Release: 100 Interface: 0 Number of Relays = 1 Module_type = 1 ELSD__1=0
and sudo usbrelay ELSD1=1 Invalid relay specification: ELSD1=1
I also have another relay of the same type but its ID_SERIAL does not end with underscore. This relay works as expected. Hopefully usbrelay can be fixed without too much trouble.
Regards Andrzej