@fadiDL what happened here was when you type n. real quick, you get debounced called with n then non-debounced called with n. - but debounced version would actually call non-debounced after timeout thus undoing the call with n. (erasing the dot). by always calling debounced version we make sure that timeout-ed call with n does not happen - it gets replaced with the 2nd n. call
@fadiDL what happened here was when you type
n.real quick, you get debounced called withnthen non-debounced called withn.- but debounced version would actually call non-debounced after timeout thus undoing the call withn.(erasing the dot). by always calling debounced version we make sure that timeout-ed call withndoes not happen - it gets replaced with the 2ndn.call