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dawnkd / curling-viz

Interactive visualization and simulation of curling
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Angle range and angular velocity #2

Open LYH6645 opened 2 years ago

LYH6645 commented 2 years ago

Hello, may I ask why the angle range in the code is [-0.2, 0.2]? And how is the angular velocity calculated?

bathtubed commented 2 years ago

The launch angle (in radians) is kept shallow because any greater and it would swing outside the boundaries of the ice at some point in the trajectory realistically.

Our physics model is from this paper [https://www.researchgate.net/publication/308044397_Pivot-Slide_Model_of_the_Motion_of_a_Curling_Rock]

They found that the magnitude of the angular velocity of the rock did not affect it's end position, just the direction it rotates. Because of this we only consider the direction of curl as -1 or +1.

LYH6645 commented 2 years ago

The launch angle (in radians) is kept shallow because any greater and it would swing outside the boundaries of the ice at some point in the trajectory realistically.

Our physics model is from this paper [https://www.researchgate.net/publication/308044397_Pivot-Slide_Model_of_the_Motion_of_a_Curling_Rock]

They found that the magnitude of the angular velocity of the rock did not affect it's end position, just the direction it rotates. Because of this we only consider the direction of curl as -1 or +1.

ok, thanks for your answer.

LYH6645 commented 2 years ago

The launch angle (in radians) is kept shallow because any greater and it would swing outside the boundaries of the ice at some point in the trajectory realistically.

Our physics model is from this paper [https://www.researchgate.net/publication/308044397_Pivot-Slide_Model_of_the_Motion_of_a_Curling_Rock]

They found that the magnitude of the angular velocity of the rock did not affect it's end position, just the direction it rotates. Because of this we only consider the direction of curl as -1 or +1.

Does the angle 0.2 refer to radians?

bathtubed commented 2 years ago

The launch angle (in radians) is kept shallow because any greater and it would swing outside the boundaries of the ice at some point in the trajectory realistically.

Our physics model is from this paper [https://www.researchgate.net/publication/308044397_Pivot-Slide_Model_of_the_Motion_of_a_Curling_Rock]

They found that the magnitude of the angular velocity of the rock did not affect it's end position, just the direction it rotates. Because of this we only consider the direction of curl as -1 or +1.

Does the angle 0.2 refer to radians?

Yes

LYH6645 commented 2 years ago

The launch angle (in radians) is kept shallow because any greater and it would swing outside the boundaries of the ice at some point in the trajectory realistically. Our physics model is from this paper [https://www.researchgate.net/publication/308044397_Pivot-Slide_Model_of_the_Motion_of_a_Curling_Rock] They found that the magnitude of the angular velocity of the rock did not affect it's end position, just the direction it rotates. Because of this we only consider the direction of curl as -1 or +1.

Does the angle 0.2 refer to radians?

Yes

Ok, thank you very much for your program and recommended paper.