Closed JervenBolleman closed 6 years ago
SELECT COUNT(*) AS ?c WHERE { ?s ?p ?o }
Must be
SELECT (COUNT(*) AS ?c) WHERE { ?s ?p ?o }
The first one is a virtuoso extension but not valid SPARQL 1.1.
Yes. Thanks a lot.
Fixed.
Must be
The first one is a virtuoso extension but not valid SPARQL 1.1.