In the event an iferror formula does not have a second argument but has a valid first argument, I am getting a TypeError: iferror() missing 1 required positional argument: 'value_if_error' Eval: iferror(_C_("Sheet1!A1") / _C_("Sheet1!A2"))
For e.g. a simple formula such as =iferror(12/3,) which works in excel will result in the above error.
In the event an iferror formula does not have a second argument but has a valid first argument, I am getting a
TypeError: iferror() missing 1 required positional argument: 'value_if_error' Eval: iferror(_C_("Sheet1!A1") / _C_("Sheet1!A2"))
For e.g. a simple formula such as =iferror(12/3,) which works in excel will result in the above error.