Keep getting error on line 3

[anoukpops]

Hello! Whatever I try to do, I keep getting this error: Undefined variable: argc in C;....... on line 3 (line 3 n both cases is if ($argc < 1)

I tried to the the user timelines - this happened when i try to run the php. Then I tried to import json, and when running the pho, the same error occurred. Any ideas what might be the problem? Thanks, Ana

[dentoir]

Hi @anoukpops

How are you starting the script? You should run the script from the command-line like this:

php timeline.php

Best,

Emile

[dentoir]

Timeout reached.