How to show dialog on particular different route in server?

[jayesh83]

Hi @dkrivoruchko It's been nice talking to you. You were really helpful and quick in earlier issues I opened #143 . Thanks for that

Now, I'm trying to implement a remote access control feature in-app, where I use ScreenStream for streaming.

I've created new rout in data.httpserver.HttpServerRxHandler file i.e. uri == HttpServerFiles.ROOT_ADDRESS + HttpServerFiles.ALLOW_REMOTE_ACCESS

On the hit of this route, I want to show the dialog in-app module somewhere that says if you want to allow remote access or not by this particular client

• on accepting I want to create a WebSocket, and let the client know somehow on which port WebSocket was created so that client can connect to that (as of now defined set of ports, seeing where I can connect)
• on reject just ignore, do nothing

Question:

• How to show dialog on that route hit

What I know/tried?

• As per my understanding, ScreenStream is using finite automata where we've defined a bunch of states, actions. Mapping each state with actions using the matrix in StateToEventMatrix file.
• I've thought of two solutions to this. 1. LocalBroadcastManager to send broadcast on route hit 2. An interface in RxHandler, which can be implemented and configured to show a dialog in Stream Viewer
• But I think the way ScreenStream is sending events from data to app module is the correct way

How to particularly go about implementing my requirement, I'm not getting, Can you help me with that?

[jayesh83]

I'll create PR on the successful implementation of Remote Control.

[dkrivoruchko]

Hi. Current version of HttpServerRxHandler has only one way communication: from AppStateMachine to HttpServerRxHandler. Keep in mind that nothing in data module has access to Android UI and because of Android restrictions we cannot show any dialog when app is minimized. In order to show user a dialog and send back user decision many things need to be implemented/updated. My first idea is to add some command channel from HttpServerRxHandler to AppService which can show user a notification with questions. Letting client to know a user choice and WebSocket configuration is a simple one - just response on request with json containing either configuration or deny. Open questions are WebSocket and remote control itself - I have no experience in this.

Bottom line - if you show me working code for remote control from web browser to android system - I will update ScreeenStream for requesting control permissions and response with WebSocket config (maybe with WebSocket too, if there will be time for this).

[jayesh83]

Hi @dkrivoruchko Coming to the bottom line, remember we've talked on the issue before #143 where I've mentioned that I'm actually making this app to app and not app to browser.

I've working code for remote control in app to app & not browser to app. So sorry for that matter

[jayesh83]

Yeah as you talked about this one way communication from AppStateMachine to HttpServerRxHandler and nothing in the data module has access to Android UI, I completely understood that.

But as you said add some command channel from HttpServerRxHandler to AppService. Can you explain exatly how to go for it?

As I believe I need to update AppStateMachine add state there and update StateToEventMatrix as well.

So can you talk about exactly in what flow I should go?

[jayesh83]

@dkrivoruchko Can you please elaborate the changes I need to make?

[dkrivoruchko]

There is no simple answer and I'm unsure if AppStateMachine or StateToEventMatrix requiere any change. Do you have code for android control in app to app? Can I have a look on part of it? How this apps talk to each other?

[jayesh83]

Yeah! It is against NDA as developing for my company but I can give you an overall idea. we can connect over meet

[jayesh83]

I'll close the issue then. Feel free to reopen, to start a discussion again