dlfivefifty / M3M6MethodsOfMathematicalPhysics

Lecture notes for M3M6 Methods of Mathematical Physics
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A question for inverting the Hilbert transform #7

Open Jiaqi-knight opened 5 years ago

Jiaqi-knight commented 5 years ago

Hello sir, Your class is worth learning in detail. Thank you for your kindness!! In lecture 19, when you derive the solution of logarithmic singular integral equations, in the end, you say "recall, we can express the solution as". What confused me is how to reach it? Recall which equation? Is any interval give this equation? My only reachable reference is your paper "Computing the Hilbert transform and its inverse". Here, when in U unit circle, H^-1=-H.

Yours, Jiaqi

Screenshot from 2019-05-14 14-48-02

dlfivefifty commented 5 years ago

That's the inverse Hilbert formula

Jiaqi-knight commented 5 years ago

Thank you, I was a little hard understand of the weighted term in the equation.

dlfivefifty commented 5 years ago

You mean the diamond? That's just the dummy variable

Jiaqi-knight commented 5 years ago

I mean why the inverse Hilbert is not just like this, 𝑢=H[f']+C, because of -H=H^-1

dlfivefifty commented 5 years ago

That’s the real line Hilbert transfoem