Closed SteinTheRuler closed 5 years ago
If the source file is in a subdirectory of base it compiles as expected, but when the file is in the base directory ("./") the compiled file is empty.
Files.zip
const { src, dest, series, parallel, watch, del } = require("gulp"); const changed = require("gulp-changed"); const fiber = require("fibers"); const print = require("gulp-print").default; const rename = require("gulp-rename"); const buildPath = dest => "./_Build/" + dest; function styleChanged () { const sass = require("gulp-sass"); const destPath = buildPath("STYLE"); const theTask = outStyle => { return src("./STYLE/**/*.scss") .pipe(changed(destPath)) .pipe(sass({fiber: fiber, outputStyle: outStyle}).on("error", sass.logError)) .pipe(rename(function (path) { var basename = path.basename; if (path.dirname !== ".") { basename = path.dirname + "." + basename; } path.basename = basename; path.dirname = "./"; })) .pipe(dest(destPath)); }; return theTask("expanded"); } function watchFiles () { watch("./STYLE/**/*.scss", styleChanged); } exports.default = watchFiles; exports.styleChanged = styleChanged;
If the source file is in a subdirectory of base it compiles as expected, but when the file is in the base directory ("./") the compiled file is empty.
Files.zip