Open Shelmith-Kariuki opened 5 years ago
Dplython could be better at dealing with external functions (like np.where
). You'd either need to make sure np.where
can handle the X
object, or use another piece of code. Dplython has some other built in functions for common cases like this. My guess is
mutate(Jinsia = if_else(X.Gender == "Female", "Mke", "Mme")
will do what you want.
Thanks for your reply. That also fails, with the following error, see screenshot attached.
Kind regards,
Shelmith
On Tue, Nov 20, 2018 at 10:54 AM Chris Riederer notifications@github.com wrote:
Dplython could be better at dealing with external functions (like np.where). You'd either need to make sure np.where can handle the X object, or use another piece of code. Dplython has some other built in functions for common cases like this. My guess is mutate(Jinsia = if_else(X.Gender == "Female", "Mke", "Mme") will do what you want.
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Sorry, looks like you're correct. How about this:
where = DelayFunction(np.where)
wf_df >> mutate(Jinsia = where(X.Gender == "Female", "Mke", "Mme"))
Woohoo!!! That works!!. I am opening another issue, on the spread function.
Hi Chris,
Thank you so much for availing yourself today. One last issue i have encountered, Problem with Spread https://github.com/dodger487/dplython/issues/97
Kind regards,
Shelmith Kariuki
On Tue, Nov 20, 2018 at 11:10 AM Chris Riederer notifications@github.com wrote:
Sorry, looks like you're correct. How about this:
where = DelayFunction(np.where) wf_df >> mutate(Jinsia = where(X.Gender == "Female", "Mke", "Mme"))
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I am trying to generate a variable, based on conditions of another variable, but the mutate function is failing.