Public Function JsonRpcCall(url As String, methName As String, args(),
Optional user As String, Optional pwd As String) As Object
Dim r As Object, cli As MSXML2.XMLHTTP60
Dim pText As String
Static reqId As Integer
reqId = reqId + 1
Set r = CreateObject("Scripting.Dictionary")
r("jsonrpc") = "2.0"
r("method") = methName
r("params") = args
r("id") = reqId
pText = toString(r)
''Set cli = CreateObject("MSXML2.XMLHTTP.6.0")
Set cli = New MSXML2.XMLHTTP60
If Len(user) > 0 Then ' If Not IsMissing(user) Then
cli.Open "POST", url, False, user, pwd
Else
cli.Open "POST", url, False
End If
cli.setRequestHeader "Content-Type", "application/json"
cli.Send pText
If cli.Status <> 200 Then
Err.Raise vbObjectError + INVALID_RPC_CALL + cli.Status, ,
cli.statusText
End If
Set r = parse(cli.responseText)
Set cli = Nothing
If r("id") <> reqId Then Err.Raise vbObjectError + INVALID_RPC_CALL, ,
"Bad Response id"
If r.Exists("error") Or Not r.Exists("result") Then
Err.Raise vbObjectError + INVALID_RPC_CALL, , "Json-Rpc Response
error: " & r("error")("message")
End If
If Not r.Exists("result") Then Err.Raise vbObjectError +
INVALID_RPC_CALL, , "Bad Response, missing result"
Set JsonRpcCall = r("result")
End Function
Original issue reported on code.google.com by telmo.ca...@gmail.com on 16 Jun 2009 at 11:48
Original issue reported on code.google.com by
telmo.ca...@gmail.com
on 16 Jun 2009 at 11:48