Closed FlyGreyWolf closed 7 months ago
hello, please check the data processing inequality (https://en.wikipedia.org/wiki/Data_processing_inequality), we have X->Y->Z, I(X;Y)>=I(X;Z)
hello, please check the data processing inequality (https://en.wikipedia.org/wiki/Data_processing_inequality), we have X->Y->Z, I(X;Y)>=I(X;Z)
OK, I got it. Thanks.
according the data processing inequality, we have: X->Z->Y, I(X;Y)<=I(Z;Y)
In the
proof of theorem 1'' of your paper, for x->g(x)->y, is this supposed to be
I(x;y)<=I(g(x);y)" instead of `` I(x;y)>=I(E;y)'' ?