Closed wangzhenlin123 closed 5 months ago
Describe the bug "nc::Shape::Shape": no overloaded function takes 4 parameters
To Reproduce Steps to reproduce the behavior: `#include
int main() { // 设置数据形状 constexpr uint32_t dim1 = 512; constexpr uint32_t dim2 = 512; constexpr uint32_t dim3 = 128; constexpr uint32_t dim4 = 3;
nc::Shape shape(dim1, dim2, dim3, dim4); nc::NdArray<int> data = nc::random::randInt<int>(shape, 0, 100); constexpr int numTests = 100; std::chrono::duration<double> totalDuration(0); for (int i = 0; i < numTests; ++i) { auto start = std::chrono::high_resolution_clock::now(); auto indices = nc::argmax(data, nc::Axis::COL); //argmax auto end = std::chrono::high_resolution_clock::now(); totalDuration += end - start; } // 输出平均执行时间 double averageTime = totalDuration.count() / numTests; std::cout << "Average time for argmax function: " << averageTime << " seconds." << std::endl; return 0;
}`
Expected behavior A clear and concise description of what you expected to happen.
Screenshots "nc::Shape::Shape": no overloaded function takes 4 parameters
This has been asked and answered many times... No it doesn't, please see the documentation.
Describe the bug "nc::Shape::Shape": no overloaded function takes 4 parameters
To Reproduce Steps to reproduce the behavior: `#include
include
include "NumCpp.hpp"
int main() { // 设置数据形状 constexpr uint32_t dim1 = 512; constexpr uint32_t dim2 = 512; constexpr uint32_t dim3 = 128; constexpr uint32_t dim4 = 3;
}`
Expected behavior A clear and concise description of what you expected to happen.
Screenshots
"nc::Shape::Shape": no overloaded function takes 4 parameters