Open huangguiyang opened 7 years ago
(i >> 0) = j;
After the simplify at simp.c, the expression 'i >> 0' will be simplified to 'i' which is an INDIR tree, thus the assignment check will be OK.
simplify
simp.c
INDIR
The same problem can be found in other identity simplification.
After the
simplify
atsimp.c
, the expression 'i >> 0' will be simplified to 'i' which is anINDIR
tree, thus the assignment check will be OK.The same problem can be found in other identity simplification.