Closed JesseEisen closed 3 years ago
$ read -d '' <<< 'Hello World'
$ echo $?
1
read
returns 1
when everything is read, which is convenient when used in a while
loop
$ read -d '' <<< 'Hello World' || true
$ echo $?
0
fortunately, you can simply hide the error from set -e
using e.g. || true
:-D
aha! I see! Thanks for replying! This should be a RTFM thing 😢
https://github.com/dylanaraps/pure-bash-bible#split-a-string-on-a-delimiter
bash version
GNU bash, version 4.4.20(1)-release (x86_64-pc-linux-gnu) Copyright (C) 2016 Free Software Foundation, Inc.
issue I just found split function cannot work with
set -e
. When I open this flag, split will fail at here string part. And I can't figure out why that is not work. Can anybody explain it? Very Thanks!