Cope with `1/y`

[strengejacke]

library(insight)
data(iris)
m <- lm(1 / Sepal.Length ~ Species, data = iris)

find_terms(m)
#> $response
#> [1] "1/Sepal.Length"
#> 
#> $conditional
#> [1] "Species"

find_transformation(m)
#> [1] "inverse"

^{Created on 2024-06-26 with reprex v2.1.0}