Closed edeprince3 closed 4 months ago
Internally, the code interprets any string 'v*' as a virtual label, but a lone 'v' should not be interpreted this way. A similar issue is present for 'o'.
fixed by commit 2780bf75eb049c037f2a3868877e183e9e068c3c
Internally, the code interprets any string 'v*' as a virtual label, but a lone 'v' should not be interpreted this way. A similar issue is present for 'o'.