Closed Physfock closed 4 months ago
I'm not sure what you mean by classical. But, If I had to get a starting point for muonic/antiprotonic helium I would use an input like the attached file, where in the XXXXXX I would put the reduced mass of muonic helium (201.1) or of antiprotonic helium (1466.8), and rename it to have .lowdin extension He-e-X-CUSTOM_MASS.txt
This is a simple HF calculation, where the mass of the negative particle is given directly from the input. The large even-tempered basis set should provide coverage for the highly localized densities of the muon and antiproton.
with m=201.1 I got TOTAL ENERGY = -402.696687921461 VIRIAL RATIO (V/T) = 2.000024358632
and with m=1466.8 TOTAL ENERGY = -2926.149607172766 VIRIAL RATIO (V/T) = 2.007799376011
I'm not sure what you mean by classical. But, If I had to get a starting point for muonic/antiprotonic helium I would use an input like the attached file, where in the XXXXXX I would put the reduced mass of muonic helium (201.1) or of antiprotonic helium (1466.8), and rename it to have .lowdin extension He-e-X-CUSTOM_MASS.txt
This is a simple HF calculation, where the mass of the negative particle is given directly from the input. The large even-tempered basis set should provide coverage for the highly localized densities of the muon and antiproton.
with m=201.1 I got TOTAL ENERGY = -402.696687921461 VIRIAL RATIO (V/T) = 2.000024358632
and with m=1466.8 TOTAL ENERGY = -2926.149607172766 VIRIAL RATIO (V/T) = 2.007799376011
Thanks for the answer! Following your example, I got a satisfactory value for the ground state of the muonic helium atom. The input below results in: -402.603948593154 a.u. while Hylleraas approach (exact variational solution for 3-body atomic problem) gives - 402.637332175538 a.u. (http://dx.doi.org/10.1051/epjconf/201922203009)
I slightly modify your suggestion as follows:
SYSTEM_DESCRIPTION='HeU Atom'
GEOMETRY e-[He] aug-cc-pVQZ 0.0000 0.0000 0.0000 multiplicity=2 addParticles=-1 U- 13s.ET.HE.U.TF 0.0000 0.0000 0.0000 m=201.1 He dirac 0.0000 0.0000 0.0000 END GEOMETRY
TASKS method = "UHF" configurationInteractionLevel ="FCI" END TASKS
However, I could not understand why in the manual (right at the beginning) when calculating "muonic water" the reduced mass for the muon never appears in the input geometry?
Hi,
I'm glad that you found a input that is working
Our manual unfortunately is a bit outdated. In the next update we will add the reduced mass option to the input description figure. Thanks for pointing this out
Can authors add more examples of calculating some classical systems like muonic/antiprotonic helium?