Closed phadej closed 6 years ago
And change (Functor f, Eq (f a)) => Eq (Coyoneda f a) to
(Functor f, Eq (f a)) => Eq (Coyoneda f a)
Eq1 f => Eq1 (Coyoneda f)
?
Would that need a major bump (following up the free 4 -> 5)?
free
And change
(Functor f, Eq (f a)) => Eq (Coyoneda f a)
to?
Would that need a major bump (following up the
free
4 -> 5)?