I tried to run MethComp::Meth(data, y=c('co_ref', 'co_exp'), item = 'id')
This gave an error, because of line#123 make.repl( data.frame(meth=rep(1,Nr),item=item) )
The function expects a data.frame with a column named "item", however, when data.frame(...) is passed a data.frame (here data[,item]) it will use the names in this data.frame instead.
These changes fixed the issue and it works with MethComp::Meth(data, y=c('co_ref', 'co_exp'), item = 'id', repl = 'time').
I have not tested it with other combinations of parameters.
I tried to run
MethComp::Meth(data, y=c('co_ref', 'co_exp'), item = 'id')This gave an error, because of line#123 make.repl( data.frame(meth=rep(1,Nr),item=item) )
The function expects a data.frame with a column named "item", however, when data.frame(...) is passed a data.frame (here data[,item]) it will use the names in this data.frame instead.
These changes fixed the issue and it works with
MethComp::Meth(data, y=c('co_ref', 'co_exp'), item = 'id', repl = 'time'). I have not tested it with other combinations of parameters.