Open LessenX opened 1 year ago
由题目给出的条件，$\varphi\left(\boldsymbol{\alpha}j\right)=\boldsymbol{\alpha}{j+1}, j=1,2, \cdots, n-1，以及 \varphi\left(\boldsymbol{\alpha}_n\right)=-a_n \boldsymbol{\alpha}1-a{n-1} \boldsymbol{\alpha}_2-\cdots-a_1 \boldsymbol{\alpha}_n，可以得到 \varphi^n\left(\boldsymbol{\alpha}_1\right)+a_1 \varphi^{n-1}\left(\boldsymbol{\alpha}1\right)+\cdots+a{n-1} \varphi\left(\boldsymbol{\alpha}_1\right)+a_n \boldsymbol{\alpha}_1=p(\varphi) \boldsymbol{\alpha}_1=\mathbf{0}，其中 p(x)=x^n+a_1 x^{n
This paragraph cannot be converted into a mathematical formula. It seems that the words containing "boldsymbol" are not converted
由题目给出的条件，$\varphi\left(\boldsymbol{\alpha}j\right)=\boldsymbol{\alpha}{j+1}, j=1,2, \cdots, n-1，以及 \varphi\left(\boldsymbol{\alpha}_n\right)=-a_n \boldsymbol{\alpha}1-a{n-1} \boldsymbol{\alpha}_2-\cdots-a_1 \boldsymbol{\alpha}_n，可以得到 \varphi^n\left(\boldsymbol{\alpha}_1\right)+a_1 \varphi^{n-1}\left(\boldsymbol{\alpha}1\right)+\cdots+a{n-1} \varphi\left(\boldsymbol{\alpha}_1\right)+a_n \boldsymbol{\alpha}_1=p(\varphi) \boldsymbol{\alpha}_1=\mathbf{0}，其中 p(x)=x^n+a_1 x^{n
This paragraph cannot be converted into a mathematical formula. It seems that the words containing "boldsymbol" are not converted