Open qlw319 opened 6 months ago
Under which circumstance is the index within the range, but the first element is nil?
The function withinRange
should take care of that, no?
!list.withinRange(index) || list.first == nil
In the process of using linkedlistqueue.Queue, when calling size is greater than 0, but when calling peek, there is a null pointer exception in line 89 of singlelinkedlist.go. We used the 1.81.1 release version.
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在什么情况下,索引在范围内,但第一个元素是零? 功能范围内应该能解决这个问题吧 !列表.范围内(指数)||列表.第一==零
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@qlw319 I still not understand how it came to that state. Is size is bigger than zero, should not the first element exist in that case?
Is it perhaps possible to write a simple test first that causes this issue? That way, we could then understand how it came to be and if we fixed the issue
ok, you're right. It does need to be checked carefully. When I'm free, I'll write a test case just to make sure.
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------------------ 原始邮件 ------------------ 发件人: "Emir @.>; 发送时间: 2024年4月12日(星期五) 下午3:50 收件人: @.>; 抄送: @.>; @.>; 主题: Re: [emirpasic/gods] fix: list.first is nil not check (PR #247)
@qlw319 I still not understand how it came to that state. Is size is bigger than zero, should not the first element exist in that case?
Is it perhaps possible to write a simple test first that causes this issue? That way, we could then understand how it came to be and if we fixed the issue
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