Provide meaningful message that method is called but not "mocked"

[Warchant]

Actual behavior:

struct Interface {
  virtual void foo() = 0;
};

Mock<Interface> mock;
Interface& face = mock.get();

face.foo(); // called, but not faked

Get this line when using with Boost.Test:

unknown location(0): fatal error: in "<testname>": unknown type

Expected behavior: See some human-readable message, that method is not faked/mocked, but called.

Version: 6d67a1d1a6f906d89217cb248b6c09abf4b33e1e

[FranckRJ]

Did you used the boost integration or the standalone version of FakeIt?

For the standalone it's kind of expected, as it must throw a type that won't be caught by the tested code (we want the exception to unwind at least until the test code), so we throw something that doesn't inherit from std::exception, ence why boost.test won't caught it.

In the integrations we try to throw something that won't be caught by the tested code but will be caught by the testing framework, as we know exactly which one it is, we can tailor the exception type to work with it.

[FranckRJ]

For me what we're doing is good enough. If you can show me a bad message while using the right configuration of fakeit (depending on your test framework) I'll reopen the issue.