Open jlowry03 opened 2 years ago
0.4.4-beta
where [x] is the cursor
;;[x] (foo) (bar) (baz)
->
;; ;;[x] (foo) (bar) (baz)
;; ;;[x] (foo (bar (baz)))
This may be related to #128, but I'm not entirely sure on that front. I might make an asciicast/script(1) of the issue and send it later.
Version
0.4.4-beta
Expected Behaviour
where [x] is the cursor
->
Actual Behaviour
->
This may be related to #128, but I'm not entirely sure on that front. I might make an asciicast/script(1) of the issue and send it later.