erdewit
commented
1 year ago my_order_id = int((time.time()%1)*(10**9))There's no need to issue an orderId, ib_insync does that for you. In the way it is done above there's actually a fair chance of ID collisions.
The error message is as below:
my_order_id = 14403343 Error 103, reqId 14403343: Duplicate order id Canceled order: Trade(contract=Stock(conId=756733, symbol='SPY', exchange='SMART', primaryExchange='ARCA', currency='USD', localSymbol='SPY', tradingClass='SPY'), order=LimitOrder(orderId=14403343, clientId=9999, action='BUY', totalQuantity=1, lmtPrice=420), orderStatus=OrderStatus(orderId=14403343, status='Cancelled', filled=0.0, remaining=0.0, avgFillPrice=0.0, permId=0, parentId=0, lastFillPrice=0.0, clientId=0, whyHeld='', mktCapPrice=0.0), fills=[], log=[TradeLogEntry(time=datetime.datetime(2023, 9, 19, 2, 45, 15, 36409, tzinfo=datetime.timezone.utc), status='PendingSubmit', message='', errorCode=0), TradeLogEntry(time=datetime.datetime(2023, 9, 19, 2, 45, 15, 37409, tzinfo=datetime.timezone.utc), status='Cancelled', message='Error 103, reqId 14403343: Duplicate order id', errorCode=103)], advancedError='')
I would get the above error message when I run the following script multiple times in a few seconds.
from ib_insync import * import time
ib = IB() ib.connect('127.0.0.1', 7497, clientId=9999)
contract = Stock('SPY', 'SMART', 'USD')
my_order_id = int((time.time()%1)*(10**9)) print('my_order_id = ', my_order_id) order = LimitOrder('BUY', 1, 420, orderId=my_order_id)
ib.qualifyContracts(contract)
trade = ib.placeOrder(contract, order)
ib.waitOnUpdate()
open_orders = ib.openOrders() print('# of open_orders = ', len(open_orders))
ib.disconnect()