Closed rileyshahar closed 1 year ago
Right now Kbox::new doesn't allow T: ?Sized, so even though Kbox is ?Sized, you won't be able to call Kbox::new with a !Sized type.
Kbox::new
T: ?Sized
Kbox
?Sized
!Sized
@nihilistkitten Thanks for catching this!
Right now
Kbox::new
doesn't allowT: ?Sized
, so even thoughKbox
is?Sized
, you won't be able to callKbox::new
with a!Sized
type.