evanxd / arudino-maxmatrix-library

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shiftRight #4

Open GoogleCodeExporter opened 9 years ago

GoogleCodeExporter commented 9 years ago
Can you show me how to use the shiftRight function to scroll the text in the 
other director.. it seems not to work here..

Original issue reported on code.google.com by bram.wer...@gmail.com on 24 Feb 2015 at 9:56

GoogleCodeExporter commented 9 years ago
[deleted comment]
GoogleCodeExporter commented 9 years ago
I would like to know how to do this also.

Since i'm trying to rotate 180 degrees the Max7219 board so the chip is on top, 
so I would need to shiftRight and Rotate the characters so they are right side 
up.

When replacing shiftLeft to shiftRight in the example code is does nothing on 
the display?!

Please help...

Thank you

Original comment by cryot...@gmail.com on 28 Feb 2015 at 7:31

GoogleCodeExporter commented 9 years ago
I found something to scroll the text from left to right (shiftRight function) 
but there are 2 problems:

1: you need to reverse your message
2: there is time needed to display a new character, I men this: when you use 
the shiftLeft function, the next character is formed net to the ledmateix and 
comes piece by piece, with my code (see below) the display is waiting until 
there is enough space on to display the whole character, it does not come piece 
by piece... Maybe we can work together to fix this?

This is my code (just the shiftRight)

void printCharWithShift(char c){

  if (c < 32) return;
  c -= 32;
    memcpy_P(buffer, CH + 7*c, 7);

      m.writeSprite(maxInUse, 0, buffer);
      m.setColumn(maxInUse + buffer[0], 0);
      for (int i=0; i<buffer[0]+1; i++)
      {
        delay(shift_speed);
        m.shiftRight(false, false);
    }
  }

This is used to reverse my message:

void reverse(){
  NUMs = strlen(msg);
  for (int i = 0, j = NUMs-1; i< NUMs/2;i++,j--) 
  {
   int temp = msg[i];
   msg[i] = msg[j];
   msg[j] = temp;
  } 
}

Original comment by bram.wer...@gmail.com on 1 Mar 2015 at 7:23

GoogleCodeExporter commented 9 years ago
Thanks for the reply,  I will look and try your code later today, and check to 
see if we can solve this problem together!

Will reply here with findings...

Original comment by cryot...@gmail.com on 4 Mar 2015 at 3:50