Closed mickmaccallum closed 8 years ago
Under Swift 3, an access level of open is required in order to be able to create a subclass outside of the class' defining module.
open
Thank you very much for your help, @0x7fffffff. I have pushed a new 7.0.0 version with your update.
Under Swift 3, an access level of
open
is required in order to be able to create a subclass outside of the class' defining module.