Closed jiegillet closed 3 years ago
Fixes #146.
From this PR, a will always be treated to be equivalent with a() in a feature, and match both a and a() in code.
a
a()
feature
There was already some code that did this for the special case of pipes, but I removed it since this is more general.
Fixes #146.
From this PR,
a
will always be treated to be equivalent witha()
in afeature
, and match botha
anda()
in code.There was already some code that did this for the special case of pipes, but I removed it since this is more general.