Closed maciejlach closed 9 years ago
Code sample:
q.async(".gw.asyncfunc", QLambda("raze"))
q)type raze 107h
is not a lambda. The users code should be:
q.async(".gw.asyncfunc", QLambda("{raze x}"))
Solution: add validation to QLambda to ensure that expression is enclosed in { and }.
{
}
Code sample:
is not a lambda. The users code should be:
Solution: add validation to QLambda to ensure that expression is enclosed in
{and}.