Open milind1097 opened 3 years ago
Yep, the Python lib is just a wrapper so everything that works with the C++ lib should work with the Python wrapper in a similar way. This is an example script to draw a fractal marker:
import cv2
import aruco
if __name__ == "__main__":
fractalmarkerSet = aruco.FractalMarkerSet.loadPredefined(aruco.FractalMarkerSet.FRACTAL_4L_6)
pixSize = 10
border = True
result = fractalmarkerSet.getFractalMarkerImage(pixSize, border)
cv2.imshow("fractal", result)
cv2.waitKey(0)
There are predefined fractal markers in aruco.FractalMarkerSet.FRACTAL_XXXX
I got the code from the aruco C++ package. In utils_fractal
there are C++ source files for creating and printing markers.
Ah alright. Thanks, I will look into it regarding how can we obtain customized markers. The pixSize = 10 that you used, is that a random number or can we take any number based on our requirements?
Thanks. :)
Hello all,
I had a question and I would be thankful if you could guide me through it. Is it possible to create a fractal marker using this aruco package?
I was wondering that in a way when we use import cv2.aruco and then obtain predefined dictionaries for aruco eg. dict_5x5_50 or dict_6x6_50, etc. Is it possible to do the same with the newly installed aruco 3.1.12 library along with this package?
Thanks in advance. :)