java 范型调用问题

package com.hello.consumer;

import com.alibaba.dubbo.config.ApplicationConfig; import com.alibaba.dubbo.config.ReferenceConfig; import com.alibaba.dubbo.config.RegistryConfig; import com.alibaba.dubbo.rpc.service.GenericService;

/**

dubbo泛化调用invoker 调用入口
@author mazhenjie

@since 2019/4/26 */ public class DubboGenericInvoker {

public static void main(String[] args) { ApplicationConfig application = new ApplicationConfig(); application.setName("api-generic-consumer");

RegistryConfig registry = new RegistryConfig();
registry.setAddress("zookeeper://172.20.30.76:2181");

application.setRegistry(registry);

ReferenceConfig<GenericService> reference = new ReferenceConfig<GenericService>();
// 弱类型接口名
reference.setInterface("calc");
reference.setVersion("1.0.0");
reference.setGroup("dubbo");
// 声明为泛化接口
reference.setGeneric(true);
reference.setApplication(application);

// 用com.alibaba.dubbo.rpc.service.GenericService可以替代所有接口引用
GenericService genericService = reference.get();

 Object name = genericService.$invoke("multi2", new String[] {String.class.getName()}, new Object[]{"2"});
System.out.println(name);

} }

直接进 if not handler: logging.warning(f'no handler for {msg.service_name}.{msg.method_name}') continue 针对这个如何修改？？？在线等

feiyuw / dubbo-py

java 范型调用问题 #7

} }