otac0n
commented
13 years ago These expressions should be roughly equivalent:
true ? foo="a" : foo="b";
and
foo = true ? "a" : "b";
However, my attempts to resolve this issue have been thwarted by the fact that swaping the binding power of the conditional causes this interpretation:
true ? (foo="a") : (foo="b"); and (foo = true) ? "a" : "b";
Whereas using the binding power of Assignment to read the expression after the colon cause this interpretation:
(true ? foo="a" : foo) = "b"; and foo = (true ? "a" : "b");
fholm
This case fails:
true ? foo="a" : foo="b"; print(foo);This case passes:
true ? (foo="a") : (foo="b"); print(foo);