Python REPL stacktrace

[khaven]

Hi, Is it possible to get full stacktrace of exception in python REPL flask example code. Right now the code is like this

`class PythonRunner: globals = {} locals = {}

def run(self, code):
    f = StringIO()
    with redirect_stdout(f):
        exec(code, self.__globals, self.__locals)
    return f.getvalue()` 

I've managed to get the full stacktrace but is it possible to exclude the info about the main.py file in the stacktrace? I want the stacktrace to look like the code was run from a file on a command line.

[khaven]

This code works well on normal compiler but doesn't work on android.

`import subprocess import traceback import sys

code = "import numpy as np\nprint(1/0)" # Example code with a division by zero error

python_executable = sys.executable # Get the path to the current Python interpreter

try: result = subprocess.run( [python_executable, "-c", code], stdout=subprocess.PIPE, stderr=subprocess.PIPE, text=True, check=True, ) except subprocess.CalledProcessError as e: print(e.stderr)`

It shows "[Errno 13] Permission denied:"

[FeodorFitsner]

subprocess won't work on Android. Mobiles don't allow spawning new processes.

[khaven]

Is it possible to directly run a file and get it's stacktrace? I see a function "runProgram" is available but is it possible to get the stacktrace from it?

[FeodorFitsner]

Working on that: https://github.com/flet-dev/flet/issues/2352 It's #1 priority right now.

[khaven]

Thank you! :)

[khaven]

Hi, I'm testing the new ^0.7.0 version. I'm trying to get the stacktrace from a file. This file was created runtime and not exists in asset. But i'm getting a message instead of a stacktrace. Is it supposed to work like that?

and if i put print("Hello") in the file and no errors then it returning empty string. Am i doing something wrong here?