Closed Lunarli closed 2 years ago
Exactly. The lossb was only related to the ytrue label. lossb get the minimum value of the ( ) of Eq.(1) when x=-0.5 A. -0.5 A is the average value of ytrue label. Why can lossb get the minimum value of the ( ) of Eq.(1) when x=-0.5 A? Because x=-0.5 A is obtained by taking the derivative of ( ) of Eq.(1)
Thanks! I got it! I'm just wondering what x stood for when I saw Eq.(1) in your paper. Actually,The lossb was the standard deviation of ytrue and independent of min function. BTW,your sharing code is pretty well. It has a complete structure and is very kind to reproduce. Thanks for sharing it !
------------------ 原始邮件 ------------------ 发件人: "foryichuanqi/Paper2022-Remaining-useful-life-prediction-by-TaFCN" @.>; 发送时间: 2022年11月25日(星期五) 中午11:21 @.>; @.**@.>; 主题: Re: [foryichuanqi/Paper2022-Remaining-useful-life-prediction-by-TaFCN] How to calculate lossb ? (Issue #2)
Exactly. The lossb was only related to the ytrue label. get min value when x=0.5*A.
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you're welcome
In your paper you said : and x was an independent variable But in you sharing code: The lossb was only related to the ytrue label Did I misunderstand? What exactly does x mean?