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[pheonix-devapps]

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	Steps		28 + 165
	1.	Equate the digits of both the numbers by prefixing imaginary Zeroes in front, and start counting upwards.	In this case,   0 2 8 + 1 6 5 --------
	2.	While summing the digits, place a dot on the previous digit for whichever digit caused the count greater than 10, and continue counting by removing the Ten's place.	In this case,   0 2o8 + 1 6 5 --------       3
	3.	While counting consider the dots in the column as an ekādhika, or +1.	In this case,   0 2o8 + 1 6 5 --------   1 9 3, which is the answer!

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[pheonix-devapps]

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[pheonix-devapps]

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