Closed rasake closed 8 years ago
We might want to use the fact that if fishA is visible to fishB, then fishB is visible from fishA. But first we should get the current solution up and working.
Do this after periodic boundary works.
Implementation sufficiently fast without grid. Closing issue.
We might want to use the fact that if fishA is visible to fishB, then fishB is visible from fishA. But first we should get the current solution up and working.