Some questions about the formula of your paper

[HLH13297997663]

In Section 3.2, I can't understand the formula: GR = E(0, 0.5π, 0) · G, How does this formula relate to the following formula (1) and (2)? How theta and phi in the code work in this formula?

[fuenwang]

Maybe you can follow my another repo for cubemap convertion: https://github.com/fuenwang/PanoramaUtility/blob/master/Utils/Equirec2Cube.py#L29

In line 16 - 29，I define the rotation for different cube faces and this is related to E(?, ?, ?) in the paper. If you are still confused about it, feel free to ask me.

[HLH13297997663]

您好，我还有些疑惑，在你的论文里，通过 spherical projection将 equirectangular image转换为cube face。那么也就是将equirectangular image上的像素坐标(X,Y)转换为cube face上的像素坐标(x,y,z)。问题是你论文和代码是通过(x,y,z)求得(X,Y)，这不是反过来了吗？

------------------ 原始邮件 ------------------ 发件人: "Fu-En.Wang"<notifications@github.com>; 发送时间: 2020年6月24日(星期三) 下午3:40 收件人: "fuenwang/Equirec2Perspec"<Equirec2Perspec@noreply.github.com>; 抄送: "恆。ヤ"<986108079@qq.com>;"Author"<author@noreply.github.com>; 主题: Re: [fuenwang/Equirec2Perspec] Some questions about the formula of your paper (#4)

Maybe you can follow my another repo for cubemap convertion: https://github.com/fuenwang/PanoramaUtility/blob/master/Utils/Equirec2Cube.py#L29

In line 16 - 29，I define the rotation for different cube faces and this is related to E(?, ?, ?) in the paper. If you are still confused about it, feel free to ask me.

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[fuenwang]

Yes, because if we directly derive xyz of cubemap from equirectangular, we cannot obtain one-to-one mapping pixel on cubemap. This means we will get a cubemap with black hole in certain area. So in here we have to use the inverse mapping to solve it and find the inverse relation.

[KOuldamer]

Hello, Could you send me the paper of this work?

[diarmaidocualain]

Hello, Could you send me the paper of this work?

https://arxiv.org/pdf/1811.05304.pdf