Open Morpheyous opened 2 years ago
if "Referer" in fuzzing_headers: fuzzing_headers["Referer"] = f'https://{fuzzing_headers["Referer"]}' return fuzzing_headers
This section of code produces a syntax error which is annoying, can you please help me fix this.
Peter
Run on python3..
if "Referer" in fuzzing_headers: fuzzing_headers["Referer"] = f'https://{fuzzing_headers["Referer"]}' return fuzzing_headers
This section of code produces a syntax error which is annoying, can you please help me fix this.
Peter