Closed imagire closed 5 years ago
Chapter 3 Page 70: The dot product does not fulfill the associative law, a.(b.c) != (a.b).c.
Good catch, I think I meant to say that scalar multiplication is associative over the dot product, but then the equation was also incorrect.
The following property is true: s (a dot b) = (s a) dot b = a dot (s b)
Chapter 3 Page 70: The dot product does not fulfill the associative law, a.(b.c) != (a.b).c.