Closed GoogleCodeExporter closed 9 years ago
ValuesIn()'s result needs to be convertible to ParamGenerator<T> if T is assignable from the base type ValuesIn()'s parameter.
Original issue reported on code.google.com by vladlosev on 28 Oct 2008 at 7:03
vladlosev
Not worth it.
Original comment by w...@google.com on 6 Mar 2010 at 6:04
w...@google.com
Original issue reported on code.google.com by
vladlosev
on 28 Oct 2008 at 7:03