Open geekelo opened 8 months ago
When you use super
without parentheses in Ruby, it implicitly passes along the arguments that were passed to the current method. This means that the arguments received by the method in the subclass are automatically forwarded to the corresponding method in the superclass.
Let's illustrate this with an example:
class Parent
def example(arg)
puts "Parent class, arg: #{arg}"
end
end
class Child < Parent
def example(arg)
puts "Child class"
super # 'arg' is implicitly passed along to the 'example' method in the Parent class
end
end
Child.new.example("Hello")
In this example, when the example
method is called on an instance of the Child
class with the argument "Hello"
, the super
keyword is used without parentheses. This means that the "Hello"
argument is automatically passed along to the example
method in the Parent
class. The output will be:
Child class
Parent class, arg: Hello
So, by using super
without parentheses, you allow Ruby to handle the passing of arguments from the subclass method to the superclass method implicitly.
In Ruby,
super
andsuper()
are related but serve different purposes. Both are used in the context of inheritance and method overriding.super
: This is used within a method of a subclass to invoke the same-named method from its superclass. It passes the arguments that were passed to the current method in the subclass.In this example,
super
is used to call theexample
method of the parent class with the argument passed to the method in the child class.super()
: This is used to invoke the same-named method from the superclass but without passing any arguments explicitly.Here,
super()
is used to call theexample
method of the parent class without passing the argument explicitly.In summary,
super
without parentheses passes along the arguments implicitly, whilesuper()
explicitly calls the superclass method without passing any arguments. The choice between them depends on the specific requirements of the overridden method in the subclass.