Open geekelo opened 2 months ago
var twoSum = function(nums, target) { let ans = []; let last = nums.length -1; // use a for loop to iterate array for(let i = nums.length - 1; i > 0; i--){ let possibleNum = target - nums.pop(); console.log(possibleNum); if (nums.includes(possibleNum)){ console.log(true); let position = nums.indexOf(possibleNum); console.log(position); ans.push(position, last ); return ans; } last--; } };
Given an array of integers nums and an integer target, return indices of the two numbers such that they add up to target.
You may assume that each input would have exactly one solution, and you may not use the same element twice.
You can return the answer in any order.
Example 1:
Input: nums = [2,7,11,15], target = 9 Output: [0,1] Explanation: Because nums[0] + nums[1] == 9, we return [0, 1]. Example 2:
Input: nums = [3,2,4], target = 6 Output: [1,2] Example 3:
Input: nums = [3,3], target = 6 Output: [0,1]
Constraints:
2 <= nums.length <= 104 -109 <= nums[i] <= 109 -109 <= target <= 109 Only one valid answer exists.