geerlingguy
commented
1 month ago 24.213 Gflops at 11.7W, for 2.07 Gflops/W
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HPLinpack 2.3 -- High-Performance Linpack benchmark -- December 2, 2018
Written by A. Petitet and R. Clint Whaley, Innovative Computing Laboratory, UTK
Modified by Piotr Luszczek, Innovative Computing Laboratory, UTK
Modified by Julien Langou, University of Colorado Denver
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An explanation of the input/output parameters follows:
T/V : Wall time / encoded variant.
N : The order of the coefficient matrix A.
NB : The partitioning blocking factor.
P : The number of process rows.
Q : The number of process columns.
Time : Time in seconds to solve the linear system.
Gflops : Rate of execution for solving the linear system.
The following parameter values will be used:
N : 10426
NB : 256
PMAP : Row-major process mapping
P : 1
Q : 4
PFACT : Right
NBMIN : 4
NDIV : 2
RFACT : Crout
BCAST : 1ringM
DEPTH : 1
SWAP : Mix (threshold = 64)
L1 : transposed form
U : transposed form
EQUIL : yes
ALIGN : 8 double precision words
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- The matrix A is randomly generated for each test.
- The following scaled residual check will be computed:
||Ax-b||_oo / ( eps * ( || x ||_oo * || A ||_oo + || b ||_oo ) * N )
- The relative machine precision (eps) is taken to be 1.110223e-16
- Computational tests pass if scaled residuals are less than 16.0
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T/V N NB P Q Time Gflops
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WR11C2R4 10426 256 1 4 31.21 2.4213e+01
HPL_pdgesv() start time Tue Aug 27 10:38:43 2024
HPL_pdgesv() end time Tue Aug 27 10:39:15 2024
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||Ax-b||_oo/(eps*(||A||_oo*||x||_oo+||b||_oo)*N)= 3.91948017e-03 ...... PASSED
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Finished 1 tests with the following results:
1 tests completed and passed residual checks,
0 tests completed and failed residual checks,
0 tests skipped because of illegal input values.
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End of Tests.
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The new Pi 5 D0 stepping model with 2GB of RAM has a 33% smaller chip, and it seems more efficient too. I'd like to see how much more efficient, by benchmarking the Pi 5 again, this time with the D0 chip.
See: https://github.com/geerlingguy/pi-overvolt/issues/4