Closed mjancarik closed 9 years ago
@Microx I figured out that if you pass options.stdio = 'inherit'
you get your logging back. Problem now is there's an null reference error on line 81.
I'd love a solution to this as well! Particularly the null reference error.
I've found a quick workaround. Instead of setting options.stdio, don't pass any options and just change line 63 in node_modules/gulp_express/index.js: from debug(data.trim());
to console.log(data.trim());
Yes, it's possible.
I have to add listener for gulp task.
node.stdout.on('data', function(data) {
console.log(data.trim());
});
node.stderr.on('data', function(data) {
console.error(data.trim());
});
please update to version 0.2.0 manually
Why do you erase support for console.log from gulp.express?
Now I have to add listener on stdout and stderr.