`for..else` doesn't work with the implicit `for array` variant

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`for..else` doesn't work with the implicit `for array` variant #1035

Closed pepkin88 closed 6 years ago

pepkin88 commented 6 years ago

Compiling this:

for [1 2 3]
  ..
else 0

gives an error Parse error on line 3: Unexpected 'ELSE'.

Working examples:

for n in [1 2 3]
  n
else 0

for [1 2 3] when 1
  ..
else 0