Closed xingmolu closed 8 years ago
Hi! I plan to generate a sprite for each css file, so sprite name need to set css filename。
spriteOutput = gulp.src(cssPath + "/*.css") .pipe(sprite({ baseUrl: 'webapp/src/images/', spriteSheetName: '??.png', // set by the css filename。 spriteSheetPath: '../images', filter: [ function(image) { return !image.meta.skip; } ] }));
I am a Chinese, not very good at English, please forgive me, thank you!
Will do it soon, thanks )
THX, I've switched to sass, not so anxious before
Hi! I plan to generate a sprite for each css file, so sprite name need to set css filename。
I am a Chinese, not very good at English, please forgive me, thank you!